Physics, asked by yani7224, 1 year ago

A particle moves from position r1 =3i+2j-6kvto position r2 = 14i+13j+9k under the action of force 4i+j+3k newton. Thework done by tgis force will be

Answers

Answered by kevinujunioroy492d
29
hey buddy here is your answer by

UDIT

work done = FORCE× DISPLACEMENT

here Force =4i+j+3k

and displacement (r2-r1)

=11i+11j+15k

then WORK=(4i+j+3k).(11i+11j+15k)

=44+11+45 joule

100 joule
Answered by aryandhar7450
6

Answer: here is your answer

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