Question

a particle moves from town A to town B with speed v and returns back to town A from town B with speed 3v the average velocity of particle is ?​

Answer 1

Given:

A particle moves from town A to town B with speed v and returns back to town A from town B with speed 3v.

To find:

Average Velocity of particle.

Calculation:

Average Velocity of an object is defined as the total displacement divided by the total time taken to cover that displacement.

$\boxed{ \sf{avg. \: v = \dfrac{total \: displacement}{total \: time} }}$

In this case , the displacement of the particle will be zero because the starting and the stopping point of the object is same. (particle starts and stops at point A).

$= > \sf{avg. \: v = \dfrac{0}{total \: time} }$

$= > \sf{avg. \: v = 0 \: m {s}^{ - 1} }$

So, average velocity is zero.

• Always remember that average velocity of a particle for a "round-trip" (complete trip) is always zero.

Answer 2

Question:-

A particle moves from town A to town B with speed v and returns back to town A from town B with speed 3v the average velocity of particle is ?

Answer:-

Average Velocity = (Total Displacement)/(Total time)

As the particle goes from town A to town B and again returns back from town B to town A, it's total displacement will be 0

→ Average Velocity = (Total Displacement)/(Total time)

→ Average Velocity = (0)/(Total time)

→ Average Velocity = 0 m/s

Ans. Average Velocity = 0 m/s

Additional Information:- (direct formula)

• When distance covered is Equal, average speed = (2 v₁ v₂)(v₁ + v₂)
• When time taken is equal, average speed = (v₁ + v₂)/2
• When motion is constantly accelerated, average velocity = (v₁ + v₂)/2