Question

A particle moves from x= +3 m to x=+6m and then to x= -2m along the x-axis . Total distance covered and displacement are

Answer 1

total displacement is just the difference in the initial (+3 m) and final (-2 m) positions of the object

So displacement = (-2) - (3) m

= -5 m

Answer 2

Answer:

The total distance covered and displacement are 11 m and -5 m.

Explanation:

Given that,

A particle moves from x = +3 m to x =+6 m and then to x = -2 m.

We need to calculate the total distance

Distance always added so the particle moves from 3 to 6 it means the distance covered by the particle is 3 m and then the particle moves 6 to zero it means the distance covered by the particle is 6 m.

Now, the particle moves to -2 it means the distance covered by the particle is 2 m.

Therefore, the total distance will be

$d=3+6+2=11\ m$

We need to calculate the displacement

Using formula of displacement

$D=final\ position - initial\ position$

Put the value into the formula

$D=-2-3=-5\ m$

Hence, The total distance covered and displacement are 11 m and -5 m.