Question

A particle moves from x = +3m to x= +6 m and
then to x = -2m along x-axis. Total distance
covered and displacement are respectively​

Answer 1

Answer:distance=11, displacement==5

Explanation:

Distance is actual path length, displacement final position minus initial position

Answer 2

Answer:

Total distance = 11 m

Displacement= -5 m.

Explanation:

Distance: It is define as the total path length travelled  by the object.It is a scalar quantity.Scalar quantity means which have magnitude only and no direction.

Displacement:It is define as the change in position when a object travel from initial position to final position.It is a vector quantity because it have both direction and magnitude.

Displacement= final position- initial position

Distance travelled by the particle when particle moves fromx=3m to x=6m and then to x=-2m

Distance from x=3m to 6m=3m

Distance travelled by the particle when particle moves from x=6 to x=-2

Distance=8m

Hence, total distance travelled by the particle=3+8=11m

Displacement travelled by the particle when partical moves x=3m to x=-2m

Initial position=3m

Final position=-2m

Displacement= final position- Initial position=-2-3=-5m

Hence, total displacement covered by the particle=-5m .

Where negative sign shows that particle moves in opposite direction.