Question

A particle moves in a circle of diameter 5m caluclate the distance and displacement after it complete 3and half round

Answer 1

Answer:

displacement =5m

distance = 54.98

Step-by-step explanation:

for every complete round it reaches same point so displacement is 0.But it travelled a half round extra so it will be equal to the diameter.

distance is 3×2πr+πr= 7πr

Answer 2

Answer:

Given,

Diameter of the circle= 5m

No. of rounds taken=

$3 \times \frac{1}{2}$

= 7/2

Step-by-step explanation:

Displacement = 0 m

As,Displacement is the shortest route between the starting and ending point of two places.

So, In this case The particle is moving round the circle and the point from where it starts , there only it stops. So no displacement occurs as startng and ending points are same.

NOW,

DISTANCE COVERED BY THE PARTICLE = CIRCUMFERENCE OF THE CIRCLE.

AS, CIRCUMFERNCE=

$\pi \times diameter$

So, 22/7 × 5m

= 110/7 m

= 15.71 m

As, The particle has taken the round for 3 ana a half times.

So, 15.71 × 7/2

= 109.97/2

= 54.985

= 54.99

( If we round off the decimal then after 5 or on 5 the digit increase by one so it becomes 54.99)

hence

Displacement= 0m

Distance = 54.99 m

HOPE I HELPED U..

PLZZ MARK AS BRAINLIEST