Question

A particle moves in a circle of radius 0.25 m at two revolutions per second. The acceleration of the particle in m/s2 is:​

Answer 1

Explanation:

Angular velocity of particle   w=2πf=2π×2=4π rad/s

Radius   r=25 cm=0.25 m

Acceleration   a=rw2=0.25×(4π)2=4π2 m/s2

Answer 2

Answer:

The acceleration of the particle is 39.5 m/s².

Explanation:

The radius of the circle, r = 0.25 m

Two revolutions are made per second by the particle.

∴ Frequency of the particle, f = 2 s⁻¹

Then angular velocity, ω of the particle can be found using the equation:

ω = 2πf

ω = 2 × π × 2

ω = 4π rad/s

We can find the acceleration, a using the following equation:

a = rω²

a = 0.25 × (4π)²

a = 4π² m/s²

a = 39.5 m/s²