Question

A particle moves in a circle of radius 0.5 m at a
speed that uniformly increases. What is the
angular acceleration of the particle of its speed
changes from 2 to 4 m/s in 4 s?​

Answer 1

Explanation:

sorry mate for the irrelevant answer

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Answer 2

Answer:

its should be like..

Explanation:

Angular acc. =(w2 -w1)/t ,where w=angular vel.

v=wr

w=v/r rad/sec

so,

w2=v2/r=4/0.5=8 rad/sec

w1=v1/r=2/0.5=4 rad/sec

Hence,

a={8-4}/4=1 rad/sec

i hope its make you clear