a particle moves in a circle of radius 1.0 cm at speed given by 2.0 t where v is in cm/sec sq t is in sec then its magnitude of the acceleration at t= 1 s
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Aradial =v^2/r
At t=1 , v =2cm/s
A =4/1cm/s2=4*10^-2m/s=4cm/s^2
Now Atanj= 2cm/s square
So Anet = underroot 2*2+4*4=underroot 20
This is the right answer
At t=1 , v =2cm/s
A =4/1cm/s2=4*10^-2m/s=4cm/s^2
Now Atanj= 2cm/s square
So Anet = underroot 2*2+4*4=underroot 20
This is the right answer
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