Question

A particle moves in a circle of radius 20 cm it's v=2t where t is in seconds and v in m/s . find tangential acceleration at 3s

Answer 1

hope this helps you.....

Answer 2

Given :

• Radius of circle = 20 cm
• Linear speed v = 2t

To Find :

• Radial and tangential acceleration at 3 sec

Solution :

The linear speed at t = 3 s :

$\tt v = 2t = 6 \: m {s}^{ - 1}$

The radial acceleration at t = 3 s :

$\tt a_r = \frac{ {v}^{2} }{r} \\ \\ \implies \tt \frac{36 \: {m}^{2} /{s}^{2} }{0.20m} \\ \\ \implies \tt180 \: m/ {s}^{2}$

The tangential acceleration :

$\tt a_t = \frac{dv}{dt} \\ \\ \implies \tt \frac{d(2t)}{dt} \\ \\ \implies \tt2 \: m /{s}^{2}$