Question

A particle moves in a circle of radius 25 cm at two
revolutions per second. The acceleration of the
particle in m/sec- is​

Answer 1

Answer:

4 π² m / sec²

Explanation:

Given :

Radius of circle = 25 cm

In term of meter :

r = 0.25 m

Also given  2  rev / sec

Then Angular velocity ( ω ) = 2 π × 2 rad / sec

ω = 4 π rad / sec .

We have to find acceleration :

We know relation between a and ω

i.e. a = r ω²

Putting values of r and ω we get

a = 0.25 × ( 4 π )² m / sec²

a = 16 × 0.25 × π² m / sec²

a = 4 π² m / sec²

Thus the acceleration of the  particle is 4 π² m / sec² .

Answer 2

2 rev/sec means → ω = 2π × 2 rad/sec

Use the formula of Acceleration a = r ω2

where r = 0.25 cm

On substituting and calculating, we get

Acceleration a = 4π2 m/s2 (2 is square)