Question

A particle moves in a circle of radius 25 cm at two revolution per second. The acceleration of the particle is

Answer 1

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Answer 2

$We know,\\a={\omega}^{2}r\\a={4\pi}^{2}\times \frac{2s}{100}\\ So,\\By putting the values,\\ 4\times({\frac{22}{7}})^{2}\times \frac{2\times 2\times157.14}{100}\\=>a={248.35ms}^{-2}$