Question

A particle moves in a circle of radius 50 cm at a speed that uniformly increases from 10 to 12 metres per second in 5 second find the angular acceleration...​

Answer 1

Answer:

★ Angular acceleration = 0.08 radius/s^2

Explanation:

★ Given,

➡ Radius of the circle,r = 50 cm = 0.5 m

➡ First velocity, v1 = 10 m/sec

➡ Second velocity, v2 = 12 m/sec

Then,

The particle’s linear speed changes from v1 = 10 m/s to v2 = 12 m/s in 5 seconds

So,the linear acceleration is a =

(v2 - v1) / t = (12 - 10) / 5 m/s^2 = 2/5 m/sec^2 = 0.4 m/sec^2

Hence, linear acceleration of the particle = 0.4 m/sec^2

We know that

linear acceleration = radius × angular acceleration

Then, by applying the value, we get,.

➡ Ang acceleration = a/r = 0.4/0.5 = 0.08 radius / sec^2

➡ Angular acceleration = 0.08 radius/s^2

Answer 2

Answer:

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