Question

A particle moves in a circle of radius 50cm at two rev/sec .The magnitude of centripetal acceleration of particle in m/s²

Answer 1

Since. we need the acceleration in m/s square
Find the circumference of the circle first...
use m as a unit instead of cm
That turns out to be Π/4m.
Π is pi...

in one second, it covers twice the circumference i.e. Π/2 m.
so its velocity is Π/2 m/s.

now centripetal acceleration is given as v square/r

a= Π sq./2 or an approx of 4.81 m/s...