Question

A particle moves in a circle with constant speed of 15 m/s . The radius of the circle is 2m Determine the centrepetal acceleration of the particle

Answer 1

Answer:

ac =112.5m/s²

Explanation:

v=15m/s

r=2m

since velocity os constant this motion is uniform

centripetal acceleration

=v²/r

=15*15/2

=225/2

ac =112.5m/s²

Answer 2

Answer:

$a=112.5\ m/s^2$

Explanation:

It is given that,

Speed of the particle, v = 15 m/s

Radius of the circle, r = 2 m

Let a is the centripetal acceleration of the particle. The formula used to find the centripetal acceleration is given by :

$a=\dfrac{v^2}{r}$

$a=\dfrac{(15\ m/s)^2}{2\ m}$

$a=112.5\ m/s^2$

So, the centripetal acceleration of the particle is $112.5\ m/s^2$. Hence, this is the required solution.