Question

A particle moves in a circle with constant
speed of 15 m/s. The radius of the circle is 2 m.
Determine the centripetal acceleration of the
particle.​

Answer 1

$\rule{200}{2}$

$\huge\boxed{\boxed{\underline{\mathcal{\red{A}\green{N}\pink{S}\orange{W}\blue{E}\pink{R:-}}}}}$

Data : v = 15 m/s, r = 2m

The centripetal acceleration of the particle

$= a = \frac{ {v}^{2} }{r} = \frac{ {15}^{2} }{2} = \frac{225}{2}$

=$\bf\boxed{\boxed{112.5 m/s^2}}$

$\rule{200}{2}$

Answer 2

Answer:

Centripetal Acceleration =

$\frac{v {}^{2} }{r}$

$\frac{15 \times 15}{2}$

112.5m/sec²

Explanation:

Plz tag me Brainleist