A particle moves in a circle with O as centre and AO=OB = 5 CM as radius. it starts from A . Calculate
a) the distance covered
b0 the displacement when it reaches B.
AionAbhishek:
figure
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Answered by
9
displacement = 5√2
distance = the curcumfreence of the circle
but I can't answer without figure
=
distance = the curcumfreence of the circle
but I can't answer without figure
=
Answered by
14
Case I )
calculate distance :
Let θ be the angle subtended between radii OA and OB.
Distance will be the total path covered between two points AB.
Distance=length of minor Arc AB = radius x θ
=5xθ=5θ
Case ii)
Calculate displacement :
As the displacement would be the shortest path between source and destination.
Displacement = Length of the chord AB.
=2r sin(θ/2)
=2x5(sinθ/2)
=10 sin(θ/2)
calculate distance :
Let θ be the angle subtended between radii OA and OB.
Distance will be the total path covered between two points AB.
Distance=length of minor Arc AB = radius x θ
=5xθ=5θ
Case ii)
Calculate displacement :
As the displacement would be the shortest path between source and destination.
Displacement = Length of the chord AB.
=2r sin(θ/2)
=2x5(sinθ/2)
=10 sin(θ/2)
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