Question

A particle moves in a circular path of radius 2 m with constant speed of 4
m/s. The magnitude of acceleration of the particle is​

Answer 1

Headnotes V ac=v2r a c = v 2 r , which is the acceleration of an object in a circle of radius r at a speed v

Centripetal acceleration formula = v^2/r

v^2 = 4

r = 2

4/2 = 2m/s

Hence acceleration is 2m/s

Answer 2

Answer is given in the pic.