A particle moves in a circular path of radius 5 m with constant speed 5 m/s.find the magnitude of its average acceleration when it completes half revolution
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Answer:
2.5π²
Explanation:
time = distance/speed
time = 2π*5/5 = 2π
velocity = displacement/ time
velocity = 10/2π = 5/π
acceleration = velocity /time
acceleration = 5/π*2π = 5/2π² = 2.5π²
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