Question

A particle moves in a circular path of radius R such that its speed v varies with a distance x as v = α√x where α is a positive constant. The acceleration of the particle after transversing a distance √2 R is?

Answer 1

Answer: alpha square / 2

Explanation:

We know that v² = u² + 2as

ATQ, v = alpha√x

v² = alpha²x

Comparing both the eqns,

'2as' is equivalent to 'alpha²x'

2ax = alpha²x

a = alpha²/2

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