Question

a particle moves in a projectile given by y=3÷4x-25÷16x^2.the angle at which
the particle is projected​

Answer 1

Answer:

Explanation:

for a projectile equation of trajectory = y = x tanФ - 0.5 g (x / v sinФ )²

comparing the equations we get tanФ = 3/4

therefore angle of projection = tan⁻¹ (3/4)

Answer 2

Answer: Ф= tan⁻¹ $(\frac{3}{4})$.

Explanation:

• We know that the equation of trajectory of a projectile motion is

            y = x tanФ - 0.5 g (x / v sinФ )²

• Given equation is y=$\frac{3}{4}x-\frac{25}{16}x^{2}$.

• When we compare both the equations we get tanФ = $\frac{3}{4}$

• Hence, the angle of projection Ф= tan⁻¹ $(\frac{3}{4})$.

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