A particle moves in a straight libe and its position x at time t is given by x^2=2+ t.What is iys acceleration?
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Answered by
1
double differentiate the equation with respect to time !!
u ll get ur answer
u ll get ur answer
Answered by
28
The equation is
x^2=2+t
Differentiation of both sides
2x.dx/dt =0+1
as dx/dt =velocity
2x.v=1
or ....
v=1/2x
v=2x^-1
Again differentiation
dv/dt=2(-1)x^-2
as dv/dt=a
so acceleration=-2/x^2
x^2=2+t
Differentiation of both sides
2x.dx/dt =0+1
as dx/dt =velocity
2x.v=1
or ....
v=1/2x
v=2x^-1
Again differentiation
dv/dt=2(-1)x^-2
as dv/dt=a
so acceleration=-2/x^2
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