Question

A particle moves in a straight line according to the relation x=t3-4t2+3t. Find the acceleration of the particle at displacement equal to zero

Answer 1

there are 3 instants when displacement of the body is 0 i.e. at t=0, t=1, t=3. By double differentiating the given eqn. we get the eqn. for acceleration i.e. a=6t-8----->(1). Substituting the values of t in (1), we get a=-8 for t=0, -2 for t=1, 10 for t=3.

Answer 2

Answer:

a=-8 for t=0,

a=-2 for t=1,

a= 10 for t=3.

Explanation:

Given: x=t3-4t2+3t

Acceleration is the rate at which velocity changes with time.

differentiating x with respect to t,

dx/dt= 3t2-8t

again differentiating dx/dt with respect to t,

d2x/dt2 = 6t-8

Now we will put t=0,1,2

putting t=0 , a= -8

t=1, a= -2

t=2, a = 3

#SPJ3