Physics, asked by ayushi062203, 1 year ago

- A particle moves in a straight line,
according to the law x = 4a(t+a sin(t/a))
where x is it's position in meters , t in sec, a is some constant, then the velocity is zero at


plz give the answer as soon as possible....​

Answers

Answered by Meghanath777
9

X=4a [t+a sin (t/a)]

(dx/dt) = 4a+ ( 4a2cos(t/an))/a

(dx/dt) = 4a + 4acos (t/a)

0 = 4a + 4a cos (t/a)

- 4a = 4a cos (t/a)

- 1 = cos (t/a)

Cos π = cos (t/a)

At t = a π , speed ends up noticeably zero


ayushi062203: hey ur ans is correct
ayushi062203: but i m not getting the second step
ayushi062203: can u pls solve it in a paper and send it to me
ayushi062203: no sorry sorry
ayushi062203: ur ans is not correct
ayushi062203: pls reply its urgent
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