Question

a particle moves in a straight line and its position x at time t is given by x^2 = 2t+1 its velocity os given by​

Answer 1

Answer:

v = 1/x

Explanation:

Given:

x² = 2t + 1

x→distance , t→time

"Velocity = displacement /time"

Differenting wrt time,

dx²/dt = d(2t)/dt +d(1)/dt

→ 2xdx/dt = 2

→ xdx/dt =1

→v = 1/x

Answer 2

Answer: 1/x

Explanation:  x^2 = 2t + 1

2 * dx/dt = 2

v = 1/x

hope it helps.