Question

A particle moves in a straight line and its velocity varies with distance travelled s as v = (10 - 2s) m/s, where sis in metre. Then Total distance traversed by particle is 10 m Total distance traversed by particle is 5 m Velocity decreases linearly with respect to time seconds In 2 Time taken in reducing the velocity to half of initial velocity is 2​

Answer 1

Answer:

17

Explanation:

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Answer 2

The final velocity of the particle is 50 m/sec.

Given,

The velocity of a particle varies with distance as v = (10-2s).

The time taken in reducing the velocity to half of the initial velocity is 2 sec. Distance traveled is 5m.

To Find,

The final velocity of the particle.

Solution,

The velocity of the particle is

v = (10-2s)

Now, the acceleration of the particle will be

a = dv/dt

a = d(10-2s)/dt

a = -2s²

Now, putting the value of s = 5m.

a = -2(5²) = -50

Now, the formula of acceleration is

(final velocity-Initial velocity)/2 = a

Now, let us assume the initial velocity is v

So,

v/2-v = -50

-v/2 = -50

v = 100, v/2 = 50 m/s

Hence, the final velocity of the particle is 50 m/sec.

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