Question

a particle moves in a straight line such that its displacement is given by x = t 3 - 6t^2 + 3t +4 find
1) it's velocity at t = 2second
2) acceleration
3) velocity when a=0​

Answer 1

Explanation:

s=t

3

−6t

2

+3t+4⇒v=3t

2

−12t+3

a=dv/dt=6t−12=0⇒t=2s

v=3(2)

2

−12×2+3=−9ms

−1