A particle moves in a straight line with a constant acceleration. It changes its velocity from10m/s to 20m/s while passing through distance 135m in t seconds, the value of t is
Answers
Answered by
1055
U=10m/s
V=20m/s
S=135m
We know,
2as=v2-u2
2×a×135=(20×20)-(10×1₩)
270a=400-100
a=300/270
a=10/9m/s2
V=u+at
20=10+10/9×t
10=10/9×t
T=10×9/10
T=9 seconds
Hope this helps
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V=20m/s
S=135m
We know,
2as=v2-u2
2×a×135=(20×20)-(10×1₩)
270a=400-100
a=300/270
a=10/9m/s2
V=u+at
20=10+10/9×t
10=10/9×t
T=10×9/10
T=9 seconds
Hope this helps
Mark this brainliest please if it helped you..!!please!
Answered by
97
"The time taken to pass through a distance of 135 m is 9 seconds.
Given
Initial velocity,
Final velocity,
Distance, s = 135 m
Solution:
Let a be the constant acceleration of the particle.
Equation
We know that the distance travelled by a body under constant acceleration is given by
We know that the final velocity of a body under constant acceleration is given by
v = u+at
Substituting equation (1) in the above equation, we get
Equating to time t, we get
Substitution
t = 9 s"
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