a particle moves in a straight line with a constant acceleration it changes its velocity from 10m/s to 20m/s while passing through a distance 135m in t seconds the value of t is"
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Hey there!
Given that a particle is moving in a straight line with a constant acceleration , and changes its velocity from 10m/s to 20 m/s while passing through a distance 135 m in t seconds, the value of t is ____
So,
Initial velocity ( u ) = 10 m/s
Final velocity ( v) = 20 m/s
Displacement ( s) = 135 m.
We know that ,
From the laws of equation ,
v² - u² = 2as
Substituting the values,
20² - 10² = 2( a) ( s)
400 -100 = 2 ( a) ( 135 )
300 = 270 a
a = 300/270
a = 10/9
Now, Use other laws of equation,
v = u + a t
20 = 10 + ( 10/9 ) t
10 = 10/9 * t
90/10 = t
t = 9 seconds.
Therefore, The time taken to change the velocity of 10 m/s to 20 m/s passing through a distance 135 m.
Given that a particle is moving in a straight line with a constant acceleration , and changes its velocity from 10m/s to 20 m/s while passing through a distance 135 m in t seconds, the value of t is ____
So,
Initial velocity ( u ) = 10 m/s
Final velocity ( v) = 20 m/s
Displacement ( s) = 135 m.
We know that ,
From the laws of equation ,
v² - u² = 2as
Substituting the values,
20² - 10² = 2( a) ( s)
400 -100 = 2 ( a) ( 135 )
300 = 270 a
a = 300/270
a = 10/9
Now, Use other laws of equation,
v = u + a t
20 = 10 + ( 10/9 ) t
10 = 10/9 * t
90/10 = t
t = 9 seconds.
Therefore, The time taken to change the velocity of 10 m/s to 20 m/s passing through a distance 135 m.
Answered by
7
Given conditions ⇒
Initial velocity (u) = 10 m/s
Final velocity (v) = 20 m/s
Displacement(S) covered by the Object = 135 m.
Using the Third Equation of the Galileo's Equation,
v² - u² = 2aS
Substituting the values,
(20)² - (10)² = 2a(135)
⇒ 400 - 100 = 270a
∴ 270a = 300
⇒ a = 10/9 m/s².
Now, Using the Galileo's First Equation of Motion,
v - u = at
20 - 10 = 10/9 × t
10 = 10/9 × t
⇒ t = 9
Hence, the time taken by the Particles moving in a Straight line is 9 seconds.
Hope it helps.
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