Question

a particle moves in a straight line with a velocity of 6m/s and 3m/s for time intervals which are in ratio 1:2 find average velocity

Answer 1

Answer:

4m/s

Explanation:

Let the times be x and 2x seconds.

Then the distances travelled will be 6x and 6x meters

Average velocity = total distance travelled / total time taken

therefore, avg vel= 12x/3x

Average velocity = 4m/s

Answer 2

AVERAGE VELOCITY IS 4 m/s

Given:

• Particle moves with 6 m/s & 3 m/s for time interval ratio of 1 : 2.

To find:

Average velocity of particle ?

Calculation:

Let the time intervals be t and 2t (where t is constant of proportionality)

Now, average velocity will be total displacement divided by total time.

$avg. \: v = \dfrac{displacment}{time}$

$\implies avg. \: v = \dfrac{(6 \times t) + (3 \times 2t)}{t + 2t}$

$\implies avg. \: v = \dfrac{6t+ 6t}{3t}$

$\implies avg. \: v = \dfrac{12t}{3t}$

$\implies avg. \: v = 4 \: m {s}^{ - 1}$

So, average velocity is 4 m/s.

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