Question

A particle moves in a straight line with constant acceleration it changes its velocity from 10 M per second to 20 metre per second while passing through a distance 135m in t seconds the value of t

Answer 1

Here we have
u = 10 ms^-1 distance, s = 135 m
v = 20 ms^-1 t = ? a = ?

From the 3rd equation of motion ,
$v { }^{2} - u {}^{2} = 2as$
therefore,
$a = v { }^{2} - u { }^{2} \div 2s$
= 400 - 100 / 270
= 300 / 270 = 10 / 9 ms^-2

we know
a = v-u/t
Therefore

t = v-u/a
= 20 - 10 / 10 /9
= 10 × 9 / 10
= 90/10 = 9 s

Hope this was helpful

Answer 2

Answer:

9 sec.

value of t= 9 sec.

i hope this answer will help you....