Question

A particle moves in a straight line with constant speed of 3 m/s for 3 seconds,then 4 m/s for 2 seconds. the V avg of the particle in given time interval is

Answer 1

$AB = 3 \: m/s \: \times 3 \: s = 9m$
$BC = 4 \: m/s \: \times 2s = 8m$

Total Distance = AB + BC
= (9+8) m
= 17 m

Total time = 3 + 2 = 5s

Average Velocity = 17/5
= 3.4 m/s