A particle moves in a straight line with initial velocity 4 m/s and a constant acceleration of 6 m/s2 . Find
the average velocity of the particle in a time interval from
(a) t = 0 to t =2
(b) t = 2s to t = 4s.
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Average velocity of the particle in a time interval from (a) t = 0 to t =2 = 10 m/s (b) t = 2s to t = 4s. = 22 m/s
Step-by-step explanation:
Using S = ut + (1/2)at²
u = 4 m/s ( initial velocity)
a = 6 m/s²
t = 2 sec
S = 4*2 + (1/2)(6)(2)²
=> S = 8 + 12
=> S = 20 m
Distance Covered = 20 m
Time = 2 Sec
Average velocity = 20/2 = 10 m/s
t = 4 sec
S = 4*4 + (1/2)(6)(4)²
=> S = 16 + 48
=> S = 64 m
Distance covered from 2 to 4 sec
= 64 - 20
= 44 m
Average velocity = 44/(4 - 2) = 22 m/s
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