A particle moves in a straight line with retardation proportional to its displacement . its loss of kinetic energy for any displacement x is proportional to [AIEEE 2004]
(a) x² (b) e^x
(c) x (d) lnx
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Answer:option b
a=−kx⇒dtdv=−kx
Also dtdx=v or dt=dvdx
∴dxvdv=−kx⇒v1∫v2vdv=−0∫xkxdx
(v22−v12)=−2kx2⇒21m(v22−v12)=21m[2−kx2]
∴ΔK∝x2
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