Question

A particle moves in a straight line with uniform acceleration. Its velocity at time t = 0
is v1 and at time t = t is V2. The average velocity of the particle in this time interval is
(v + v2)/2. Is this correct? Substantiate your answer.​

Answer 1

Average velocity=

$\frac{total \: distance}{total \: time}$

Now,total time =t

Also,v2=v1 + at or a=

$\frac{v2 - v1}{t}$

Thus,s=

$\frac{v2 - u2}{2ab} = \frac{ {v2}^{2} - {v1}^{2} }{2 (\frac{v2 - v1}{t} )}$

Thus,s=

$\frac{(v2 + v1)t}{2}$

Thus,average velocity is

$\frac{(v2 + v1)}{2}$

Answer 2

Average velocity=

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