A particle moves in circle which has a centre O. It start motion from point A and reach to point B (As shown in figure). Calculate its distance and displacement from A to B. Given that diagonal of square is 4cm.
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ANSWERGiven that,
ANSWERGiven that,Angle of A and B=60
ANSWERGiven that,Angle of A and B=60 0
ANSWERGiven that,Angle of A and B=60 0
ANSWERGiven that,Angle of A and B=60 0 Now, distance of a particle between A and B
ANSWERGiven that,Angle of A and B=60 0 Now, distance of a particle between A and BDistance travelled = length of arc AB
ANSWERGiven that,Angle of A and B=60 0 Now, distance of a particle between A and BDistance travelled = length of arc AB =
ANSWERGiven that,Angle of A and B=60 0 Now, distance of a particle between A and BDistance travelled = length of arc AB = 360
ANSWERGiven that,Angle of A and B=60 0 Now, distance of a particle between A and BDistance travelled = length of arc AB = 36060
ANSWERGiven that,Angle of A and B=60 0 Now, distance of a particle between A and BDistance travelled = length of arc AB = 36060
ANSWERGiven that,Angle of A and B=60 0 Now, distance of a particle between A and BDistance travelled = length of arc AB = 36060 ×2πR
ANSWERGiven that,Angle of A and B=60 0 Now, distance of a particle between A and BDistance travelled = length of arc AB = 36060 ×2πR =
ANSWERGiven that,Angle of A and B=60 0 Now, distance of a particle between A and BDistance travelled = length of arc AB = 36060 ×2πR = 3
ANSWERGiven that,Angle of A and B=60 0 Now, distance of a particle between A and BDistance travelled = length of arc AB = 36060 ×2πR = 3πR
ANSWERGiven that,Angle of A and B=60 0 Now, distance of a particle between A and BDistance travelled = length of arc AB = 36060 ×2πR = 3πR
ANSWERGiven that,Angle of A and B=60 0 Now, distance of a particle between A and BDistance travelled = length of arc AB = 36060 ×2πR = 3πR
ANSWERGiven that,Angle of A and B=60 0 Now, distance of a particle between A and BDistance travelled = length of arc AB = 36060 ×2πR = 3πR Hence, the distance covered by the objects is
ANSWERGiven that,Angle of A and B=60 0 Now, distance of a particle between A and BDistance travelled = length of arc AB = 36060 ×2πR = 3πR Hence, the distance covered by the objects is 3
ANSWERGiven that,Angle of A and B=60 0 Now, distance of a particle between A and BDistance travelled = length of arc AB = 36060 ×2πR = 3πR Hence, the distance covered by the objects is 3πR
ANSWERGiven that,Angle of A and B=60 0 Now, distance of a particle between A and BDistance travelled = length of arc AB = 36060 ×2πR = 3πR Hence, the distance covered by the objects is 3πR
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