A particle moves in the x-y plane under the action of the force F such that
the value of it's linear momentum p at any time t is p(x)= 2 cost and pſy) =2 sint
. The angle between F and p at a given time t will be
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Answer:
Force is defined as the rate of change of momentum.
P
x
=2cost
P
y
=2sint
P
=2cost
i
^
+2sint
j
^
F=
dt
dP
F
x
=−2sint
F
y
=2cost
From law of vector dot product,
A
.
B
=ABcosθ
Where θ is angle between them.
cosθ=
AB
A
.
B
Here,
cosθ=
FP
F
.
P
cosθ=
FP
−2cost×2sint+2cost+2sint
cosθ=0
θ=90°
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