Question

A particle moves in the x-y plane with only x component of acceleration at 2m/s^2. The particle starts from the origin. With an initial velocity having x component of 8m/s and y component of -15m/s velocity at t is

Answer 1

Answer:

solved

Explanation:

d²x/dt² = 2  m/s²

d²y/dt² = 0 m/s²

dx/dt = 2t + 8 = vx

dy/dt = -15 = vy

v = √ vx² + vy² = √ (2t+8)² + 225 = √(4t² + 32t + 289)