Question

A particle moves in the x-y plane with velocity vx =8t-2 and vy= 2. If it passes through the point x=14 and y=4 at t=2 sec, the equation of the path is :


x=y^2-y+2

x=y^2-2

x=y^2+y-6

None of these

Answer 1

any comments ...wlcm

Answer 2

That's all I got... I tried to manage it in a quite small space as I didn't want to continue it on next page.. Any confusions?