Question

A particle moves in the xy-plane with constant acceleration a directed along the negative y-axis. The equation of path of the particle has the form y=bx−cx ^2
, where b and c are positive constants. The velocity v of the particle at the origin of coordinates will be
in my book it says yf you differentiate with respect to t
it becomes dy/dt=b*dx/dt+c*2x*dx/dt
but x is not dependent on time how can we differentiate it
can you explain

Answer 1

Answer:

A particle moves in the xy-plane with constant acceleration a directed along the negative y-axis. The equation of path of the particle has the form y=bx−cx2, where b and c are positive constants

Answer 2

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A particle moves in the xy-plane with constant acceleration a directed along the negative y-axis. The equation of path of the particle has the form y=bx−cx2, where b and c are positive constants. The velocity v of the particle at the origin of coordinates will be. A.