A particle moves in the xy plane with only an x-component of acceleration of 2m/s^2. The particle starts from the origin at t=0 with an initial velocity having an x-component of 8m/s and y-component of -15m/s. What is the velocity of particle after time t ?
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For x – bearing first, Applying the eqns. of movement, v1 = u1 + at v1 = 8i + 2i*t => (8 + 2t)I For y – heading Acceleration is zero.
In this manner speed stays consistent. v2 = u2 v2 = - 15j Thus, resultant speed of molecule at time t from conditions. v = v1 + v2 v = (8 + 2t)i – 15j m/s.
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