Physics, asked by ankush4387, 11 months ago

A particle moves in x-y plane with a velocity
V = 2y î+4j. Equation of the path followed by
the particle is
(1) x = y^1/2
(2) y = x^1/2
(3) 4x = y^2
(4) 4y = x^2​

Answers

Answered by shivamabs2002
5

Answer:

equation of partical should follow option 1 and 2.....

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