Physics, asked by ankushsingh795, 1 year ago

A particle moves in x y plane with a velocity vx=8t-2 and vy=2 .It passes through the point X=14 and y=4 at t=2s the equation of path is

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Answered by maneeshsaxena1pavvd0
0
VX=8t_2
by=2
x=14
y=4
t=2s
14v=8t_2
4v=2
2v=1
7*2v=16s_2
8s_1=7/2

ankushsingh795: sorry but i am unable to understand
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