Physics, asked by harshitagarwal624, 11 months ago


A particle moves in xy plane with a velocity given by v = (8t - 2)i +2j. If it passes through the point (14,4)
at t = 2 sec., then equation of the path is
(C) x + y - y2 = 2 (D) -x - y + y2 = 2
(A) x- y + y2 = 2 (B) -x + y + y2 = 2

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Answered by shivpotkar7723
2

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harshitagarwal624: Thank u
Answered by XanshikaX206
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