Question

A particle moves in xy plane with a velocity given by v = (8t - 2)i +2j. If it passes through the point (14,4)
at t = 2 sec., then equation of the path is
(C) x + y - y2 = 2 (D) -x - y + y2 = 2
(A) x- y + y2 = 2 (B) -x + y + y2 = 2
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Answer 1

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Answer 2

Answer:

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