Question

A particle moves on a circle of radius 6 cm, with
constant speed. The particle completes one
revolution in every 5 sec. What will be the path length
of the particle after 12.5 sec?​

Answer 1

Step-by-step explanation:

r=5cm=5×10−2m

T=0.2πs

Velocity, v=T2πr

v=0.2π2π×5×10−2=0.5m/s

The centripetal  acceleration of the particle in circular motion is given by

a=rv2

a=5×10−20.5×0.5=5m/s2

I think so it would be like this