Question

A particle moves on a circular path of radius 5m with constant speed 5 m/s find the magnitude of its average acceleration when it completes half revolution

Answer 1

r = 5 m
v = 5 m/s
$a \: = \: {v}^{2} \: \div \: r$
$a \: = \: {(5 \: m{s}^{ - 1})}^{2} \: \div \: (5 \: m)$
$a \: = 5 \: m {s}^{ - 2}$