Question

A particle moves on a rough horizontal ground with some initial velocity say V°. If
of its kinetic energy
is lost due to friction in time t°, then coefficient of friction between the particle and the ground is :​

Answer 1

Explanation:

If energy becomes 14 th .

34 th energy is lost, Velocity becomes v02 under retardation μg

v02=v0−μgt0

μ=v02gt0

Hence a is the correct answer

Answer 2

Answer:

pls tell me your physics guide's name..V●ᴥ●V