a particle moves on a straight line at constant speed v. At certain time it is at point p on straight line path. o is a fixed point. show that op vector × v vector is independent of position p.
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For better understanding see the figure.
The particle moves on the straight line PP' at speed v.
According to the figure,
OP x v = (OP) v sinФ n = v(OP) sinФ n = v(OQ) n
So, we can see that from the figure,
OQ = OP sin Ф = OP' sin Ф'
So, the magnitude of OP x v remain constant irrespective of the position of the particle.
Therefore , OP x v is independent of position P.
Hope it helps!
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