A particle moves on astraight line in such way that it covers 1st half distance with speed 3 m per s and next half distance in 2 equal time intervals with speed 4.5 m per s and 7.5 m per s respectivly find average speed of the particle
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Answer:
Answer is 4 m/s
Explanation:
Let the first half distance be V1 and 2nd half be V2
V1 = 3m/s.
V2 = (4.5+7.5) / 2. [by using (V¹+V²)/2]
= 6 m/s
Now, Avg. Speed = (2V1.V2) / V1+V2
= (2.3.6)/(3+6)
= 36/9
= 4 m/s
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