Question

A particle moves on circular path of radius 7 metres with constant speed 7m/s the magnitude of average velocity during revolution through quarter circle​

Answer 1

The acceleration is 7 m/s².

Explanation:

Given that,

Radius = 7 m

Speed = 7 m/s

At constant speed, the acceleration is

We need to calculate the acceleration

Using formula of acceleration

$a=\dfrac{v^2}{r}$

Where, v = speed

r = radius

Put the value into the formula

$a=\dfrac{7^2}{7}$

$a=7\ m/s^2$

Hence, The acceleration is 7 m/s².

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