A particle moves on the circumference of a circle of radius 'r’ with a constant speed. The centripetal acceleration of the particle
a)² when the radius of the circle is 5 cm and its period of revolution is 0.2 π seconds is if the particle moves with a speed equal to that which it would have acquired by falling freely, when dropped, through half the radius of the circle is
b)when the radius of the circle is 5 cm and its period of revolution is 0.2 π seconds is if the particle moves with a speed equal to that which it would have acquired by falling freely, when dropped, through half the radius of the circle is
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0
Answer:
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Answered by
1
Explanation:
ANSWER
To find speed acquired by free fall
Here s=
2
r
,a=g
⟹
2
r
=
2
1
gt
2
⟹t=
g
r
Therefore
v=gt=
rg
The following speed is same in circular motion of radius r
Centripetal acceleration ,a
c
=
r
v
2
=
r
rg
=g
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